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Solve for y: x + 3y > 9.
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@uri
@Luigi0210
Solve for y means to isolate the y by using inverse operations.
Inverse operations: multiplication <-> division addition <->subtraction
x + 3y > 9 3y > 9.-x \[y > \frac{9}{3}- \frac{x}{3} \rightarrow y > 3- \frac{x}{3} \]
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ok so i got 3y>9-x what do i do now
Remember that the 3 is being multiplied by the y. You need to do the inverse operation to separate it. What you do to one side, you must do to the other.
multiply by 3
\(3 \times y = 9 - x\) Look at it in expanded form...
i got it is y>1/3x-3
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Right idea, but you made a mistake, can you find it?
i put 1/3
You reversed the 9 and the negative x, which would be ok if you kept the negative sign with the x.
9-x = -x+9
ohhh i see i corrected it :) thanks
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