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please help What does the product (-5 - 2i)(3 + 7i) equal? A) -15 - 14i B) -1 - 41i C) -29 -41i D) -1 + 41i E) -29 + 41i
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Just do regular distribution. Remember that i^2=1.
multiply as follows: (-5)(3) = -15 (-5)(7i) = -35i (-2i)(3)= -6i (-2i)(7i) = -14i^2
so you have -15-35i-6i-14i^2
thats what i got. i see what i did wrong
Oops, I meant i^2=-1. Sorry!
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now combine like terms so you have -15 -41i -14i^2
now you substitute the i^2 = -1 like Alwayshte Booworm said
hold on afk
so you have -15 -41i -14(-1) -15 -41i+14
Multiply in this manner: (-5 - 2i)(3 + 7i) = -5(3 + 7i) -2i(3 + 7i) = -15 -35i - 6i - 14i^2 = -15 -41i -14(-1) = 14 - 15 - 41i = -1 - 41i
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so combine like terms and you have -1-41i
thanks
yw :)
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