Question

factor!
x^2+4x+3

Answer 1

x^2+3x+x+3 =0
(x+3)(x+1)=0
x =-3 or x=-1

Answer 2

well, \[x ^{2}+4x+3=x ^{2}+4x+4-1=(x +2)^{2}-1\]

that's your answer!

Answer 3

no! @ankit042 that's solving not factorizing!

Answer 4

oooops! my HUGE mistake! @ankit042 , your right. the solutions are x=-3and x=-1, thus we can factorize it as (x+3)(x+1)

Answer 5

well,my method works too. recall the formula \[a ^{2}-b ^{2}=(a+b)^{2}*(a-b)^{2}\]

Answer 6

so a=x+2 and b=1 plug in the formula above yields the same result

Answer 7

soory no square!

Answer 8

ok help once more...

Answer 9

find x: 9x^2+6x+1

Answer 10

guys no time to explain....I have 10 minutes!!!

Answer 11

while you can factoize it immediately which should be (3x +1)^2 so 3x=-1, x=-1/3

Answer 12

my answer definitely helps, right?

Answer 13

yes it helps thanks!