a rectangle has an area of 96 sq ft if the width of the yard is 4 ft less than the length, what is the perimeter in ft of the yard: that's my problem.. my question is what is the number that will help me figure this out or how do i get that number to find my answer
put say \(x\) as the length, then \(x-4\) is the width because it says the width of the yard is 4 ft less than the length
the area is length times width, and so you have to solve \[x(x-4)=94\] can you do that?
oh ok yes i can
ok then once you find \(x\) you still have to find the perimeter, which will be \[x+x+x-4+x-4\] better known as \[4x-8\] don't forget that step at the end
let me know what you get for \(x\)
ok
44 my final answer
hmmm i think i got 40 what did you get for \(x\) ?
dammit well it doesnt matter ur correct
i used 24
oh damn i made a mistake above, it is \(96\) not \(94\) you have to solve \[x(x-4)=96\]
\[x(x-4)=96\] \[x^2-4x=96\] \[x^2-4x-96=0\]\[(x-12)(x+8)=0\]
then if \(x=12\) you have \(4\times 12-8=40\)
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