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help mee please. If x-y=20, and x^2-y^2=50, what is the value of X
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Replace y in the second equation with x-20 from the first equation.
x-y not x-20 Mertsj
How so?
@mertsj, are you using the elimination by substitution method
When you replace a variable, that means substitute something else for it.
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ok. so now its x^2 - (x-20)^2=50
yes
so after you distribute the negative sign it becomes x^2(-x+20)^2=50
\[x^2-(x^2-40x+400)=50\]
\[x^2-x^2+40x-400=50\]
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what did you just do.
\[40x=450\]
Expand (x-20)^2 Remove the parentheses by changing everything inside to its opposite.
|dw:1374629077222:dw|
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