Question

Solve the triangle.

A = 46°, a = 33, b = 26
anyone out there want to help a lost soul?

Answer 1

did you draw one?

Answer 2

the first step is to draw a reasonable looking triangle

Answer 3

\[\frac{ 33 }{ \sin46 } =\frac{ 26 }{ sinB}\]
\[SinB =\frac{ \sin46 * 26 }{ 33 } = 0.56\]
B= \[\sin^{-1} 0.56 =34. 52°
angle for C = 180°-46°-34.5° = 99.5°.

Answer 4

@lap. may arrive at the correct answer, but i have to point out that the triangle is not quite right

Answer 5

so \[\frac{ 33 }{ \sin46 } =\frac{ c }{ \sin 99.5 }\]
\[c = \frac{ 33 *\sin99.5 }{ \sin 46 } =45.25\]

Answer 6

see for this one I solved for angle B by setting up a triangle but I have no idea how to solve for side c to get angle C

Answer 7

wait how'd you get angle C?

Answer 8

see previous post angle for C = 99.5° and you have to use The Law of Sines : http://www.mathsisfun.com/algebra/trig-sine-law.html

Answer 9

thanks!! i understand now.

Answer 10

you are welcome :)