Find the derivative of f(x) = 3x + 8 at x = 4. Help please :(
derivative is 3
thanks but how did you get it?
first differentiate the equation this would be f'(x)=3+0 now put value of x and get the result which is 3
im confused, i dont know how you got that :(
basic rule of differentiation! if u differentiate anything of the form nx where n is a constant you get the constant after differentiating. and if u differentiate a constant like 8 you get 0
use the power rule which is taking the power moving it down and subtracting it by 1 so \[\frac{d}{dx}x^{n}=nx^{n-1}\]
\(\frac{d}{dx}a^n = na^{n-1}\) in this case n = 1 and 1-1 = 0 and \(x^0=1\)
im still confused guys, im sorry :/
@britanny_ and how is that possible??
Britanny, what are you doing? Go home, you're drunk.
@britanny_ u need the derivative first i think! if you put the value then then you wont get the answer!
lol
ok guys o-o be nice
that kinda just made my day (sadly )
fine whatever you answer it in a way she can understand.
:/ could you help me @britanny_ i have like 4 more of these to do and im confused :(
@britanny_ i think you missed that this is a calculus question - your method is not correct here. @iluvvyyhu do you know how to find the derivative of y = 3x +8?
no i dont :/ and the class im taking is precalc but its online and they didnt have a good explanation
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