Question

i need help pleez!
how do you solve sin^2x + cosx=2

Answer 1

i find that it is a no solution problem but i dont think that can be right..

Answer 2

recall that \[\sin ^{2} x = 1- \cos ^{2}\]

so now we have

\[1 -\cos ^{2}x +cosx = 2\]

Bring the 2 over by subtracting from both sides
let y = cosx
\[-y ^{2} +y +1\]

can you factor that...

Answer 3

Woops I meant\[-y ^{2} +y -1\] haha.. yea factor this.

Answer 4

it isnt factorable right?

Answer 5

it is...try