Mathematics
17 Online
OpenStudy (anonymous):
anyone know how please and thanks (picture)
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OpenStudy (anonymous):
OpenStudy (anonymous):
to move it 6 units to the left, replace \(x\) by \(x+6\)
OpenStudy (anonymous):
top one is \(x+6-3=x+3\)
OpenStudy (anonymous):
second one is \(4(x+6)=4x+24\)
OpenStudy (anonymous):
alright now the only major problem i have is putting the answer in i got that same answers but not sure what goes in what place
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OpenStudy (anonymous):
ok very first slot should be \(x+3\) and the slot immediately to its right should be \(x<-6\) although i guess you just put in \(-6\)
OpenStudy (anonymous):
then below that would be \(4x+24\) and to the right of that \(x>-6\)
OpenStudy (anonymous):
now the factor of 4 would that be (x+4)4?
OpenStudy (anonymous):
multiply by 4
OpenStudy (anonymous):
\(4x-12\) for the first one, \(16x\) for the second
put 0 in both slots on the right
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OpenStudy (anonymous):
wow! thanks babe!!
OpenStudy (anonymous):
satellite73 the 4x-12 and 16x were wrong! =(
OpenStudy (anonymous):
it says horizontal compression, which means the value before x should be smaller, so i think it's divide by 4, not multiply by 4
OpenStudy (anonymous):
(x-3)/4 and x
OpenStudy (anonymous):
im confused so the 4x-12 is (x-3)/4?
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OpenStudy (anonymous):
yes, and the other instead of 16x it's just x
OpenStudy (anonymous):
4x/4 = x
OpenStudy (anonymous):
so how do i enter the first one if you dont mind telling me
OpenStudy (anonymous):
is (x-3)/4 not acceptable answer for h(x) first line? what about (x/4)-(3/4)
OpenStudy (anonymous):
that one didn't work!
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OpenStudy (anonymous):
ok try (x/4)-3
OpenStudy (anonymous):
what about the bottom one? was x right?
OpenStudy (anonymous):
yeah!
OpenStudy (anonymous):
if x was right then the first one should be x/4-3
OpenStudy (anonymous):
just a matter of how you type it in, but the correct answer is (x/4)-3
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OpenStudy (anonymous):
sorry hon good luck
OpenStudy (anonymous):
you were right thank you!!!!
OpenStudy (anonymous):
yw