Question

if a,b,c are are in Arithmetic progression, prove bc-a^2, ca-b^2, ab-c^2 are also in AP.

Answer 1

Well, if a, b, and c are in arithmetic progression, what immediately follows?

Answer 2

b-a=c-b
i did (ca-b^2)-( bc-a^2)=(ab-c^2)-(ca-b^2) but i am getting (a-b)= (b-c)

Answer 3

And what's wrong with that? :P
Does it not follow that if
p = q
then
-p = -q
?
;)

Answer 4

so i can multiply both sides with -1 ??

Answer 5

Naturally :P
1 , 2, and 3 are in arithmetic progression... so
2 - 1 = 3 - 2
true enough, but also...
1 - 2 = 2 - 3

LOL
^_^

Answer 6

thanks