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Mathematics 25 Online
OpenStudy (lucaz):

how do I find the function of the 2nd graph? http://img15.imageshack.us/img15/3803/ndy4.jpg

OpenStudy (lucaz):

yes

OpenStudy (lucaz):

I got, it can be solved by trig identity, tan(a+a) = tan(2a)

OpenStudy (anonymous):

really? could u show us i got a identitie but it dont works

OpenStudy (fifciol):

the slope is tan a =1/2 so alpha =26,56 degrees .so tan of 2*alpha =4/3

OpenStudy (fifciol):

y intercept remains the same

OpenStudy (anonymous):

4/3 is the slope

OpenStudy (fifciol):

yes

OpenStudy (lucaz):

from the 1st graph tan(a)=1/2 on the 2nd m = tan(2a) = tan(a+a) = [tan(a)+tan(a)] / 1-tan(a)xtan(a) then plug tan(a)=1/2

OpenStudy (anonymous):

that was the identitie but i donw know why i plug 1 for the value of tan(a) that was the reason it dont works

OpenStudy (lucaz):

plug 1/2 from the first slope

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