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how do I find the function of the 2nd graph? http://img15.imageshack.us/img15/3803/ndy4.jpg
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yes
I got, it can be solved by trig identity, tan(a+a) = tan(2a)
really? could u show us i got a identitie but it dont works
the slope is tan a =1/2 so alpha =26,56 degrees .so tan of 2*alpha =4/3
y intercept remains the same
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4/3 is the slope
yes
from the 1st graph tan(a)=1/2 on the 2nd m = tan(2a) = tan(a+a) = [tan(a)+tan(a)] / 1-tan(a)xtan(a) then plug tan(a)=1/2
that was the identitie but i donw know why i plug 1 for the value of tan(a) that was the reason it dont works
plug 1/2 from the first slope
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