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Mathematics 13 Online
OpenStudy (anonymous):

using the grouping method factor the polynomial completely 5x^5+30x^3+25x

OpenStudy (uri):

What's common in this? @Torrie11

OpenStudy (anonymous):

First take 5x out of the equation for they all share it. 5x (x^4+6x^2+5) Now a polynomial such as this: (x^4+6x^2+5) can be factored just as you factor (ax^2+bx+c), except all degrees are doubled. Now x^2+6x+5 would be factored as (x+5)(x+1) All you do now is double the degrees of x. (x^2+5)(x^2+1) Then tack on that 5x you took out to begin with: 5x(x^2+5)(x^2+1)

hero (hero):

That's not the factor by grouping method.

hero (hero):

@flixoe

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