Question

im having some problems with my math if someone could help id be eternally greatful
1. What are the solutions of 3x2 = 18x?
3.Identify the solutions of 2x2 + 13x + 6 = 0.
4.Solve x2 − 7x + 12 = 0.
7.What are the x-intercept(s) of the graph of y + 6 = x2 − x?
10.What is true about the solutions of a quadratic equation when the radicand in the quadratic formula is negative?
15.Where does the graph of y = 2x2 − 9x − 5 cross the x-axis?
thanks for the help everyone that awnsers

Answer 1

well, assuming zero is already taken care of ... divide by x

Answer 2

I will help u one at a time so number 1....

\[3x^2=18x\]

\[3x^2-18x=0\]

\[3x(x-6)=0\]

\[x=0,6\]

Answer 3

alright, I think I understand that one but I got a negative

Answer 4

mostly cuz I made a typo but thanks

Answer 5

amistre what do you mean?

Answer 6

3x2 = 18x

it should be obvious that zero is one solution; assuming that we need another one we can then divide each side by x and solve

Answer 7

3x2 = 18x

3x = 18

Answer 8

oh,... lol thanks that makes a lot more sense then what I was trying

Answer 9

hows about the next one?

Answer 10

can you factor it? or what methods are available to you?

Answer 11

x = 1 over 2, x = 6

x = −1 over 2, x = −6

x = −3 over 2, x = −2

x = 3 over 2, x = 2
those are the choices

Answer 12

if you have choices, then the easiest thing to do is to test them out ...

Answer 13

try the non fractions

Answer 14

2x2 + 13x + 6 = 0

2x2 + 13x = -6

we are going to need some negative values in order to get this to work out

Answer 15

does x=-2 work? of not, then its the other one