Question

multiply. then simplify if possible.
problem below

Answer 1

\[\frac{ 6t+6 }{ t^3+2t^2 } \times \frac{ t^3-3t^2+2t }{ 3t+3 }\]

Answer 2

i factored it to

\[\frac{ 6(t+1) }{ t^2 (t+2) } \times \frac{ t(t-2)(t-1) }{ 3(t+1) }\]

Answer 3

first factorise the tops and bottoms of the fractions
eg 6t + 6 = 6(t + 1)
t^3 - 3t^2 + 2t = t(

Answer 4

ok now cancel out the like terms
eg (t +1) disapperas from top and bottom

Answer 5

also t /t^ = 1/t and 6/3 = 2

Answer 6

* t / t^2 = 1/t

Answer 7

so its now: \[\frac{ 6 }{ t^2(t+2) } \times \frac{ t(t-2)(t-1) }{ 3 }\] ?

Answer 8

now do the 2 thing i said above

Answer 9

how would i type that?

Answer 10

it comes to

2(t - 1)(t - 2)
------------
t(t + 2)

Answer 11

and thats it?