Find the x- and y-intercept of the line. x + 4y = 36? help
notice this line |dw:1374705041758:dw| there are 2 points there on point hits the y-axis, thus called the y-intercept another point hits the x-axis, thus called the x-intercept notice the one hitting the "y", y = 2, what is "x"? notice the one hitting the "x", x = 4, what is "y"?
so what do i do after that?
x-intercept is 9; y-intercept is 36. is that the answer?
well, notice when the line hits the "y", the x = 0 when it hits the "x", y =0 how to find the intercepts? if you want the x-intercept, set \(\bf y = 0\) in the equation and solve for "x" if you want the y-intercept, set \(\bf x = 0\) in the equation and solve for "y"
x+4y=36 set y=0 first to get your x-int x+4(0)=36 x=36 then set x=0 to get y-int 0+4y=36 y=9
thanks jojo, i juss had to switch them right?
yes
Write y = mc012-1.jpgx + 4 in standard form using integers.\[Write y \frac{ 3 }{ 5 }x + 4 \in standard form using integers.? help jojo!\]
add y= to the second equation
well standard form all it means that your equation should look in this form ex. x+y=0 meaning all the variables on one side so for this one move 3/5x to the side where y is... ill show you y=35x+4∈ y-35x=4∈
–3x – 5y = 20 would that be the answer?
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