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OpenStudy (anonymous):
Help y = -2x^2 - 12x + 1
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Directrix (directrix):
What are the instructions?
OpenStudy (anonymous):
Identify the vertex for the graph of y = -2x^2 - 12x +1
Directrix (directrix):
Do you know how to begin in finding the vertex?
OpenStudy (anonymous):
nope
OpenStudy (anonymous):
im really bad at algebra so that is why i need help
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OpenStudy (luigi0210):
I doubt you know derivatives? xD
OpenStudy (uri):
I was looking forward to solve a Quad equation......
OpenStudy (anonymous):
lol luigi i have no clue what that is
OpenStudy (mertsj):
The x coordinate of the vertex is:
\[x=\frac{-b}{2a}\]
OpenStudy (mertsj):
After you find that, plug the answer into your equation and find y.
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OpenStudy (anonymous):
You may want to get the answer by completing square.
y = -2x^2 - 12x + 1
= -2 (x^2 + 6x ) + 1
= -2 [x^2 + 6x + (6/2)^2- (6/2)^2] + 1
= -2 (x^2 + 6x + 9 - 9) +1
= -2 (x^2 + 6x + 9 ) - 9(-2) + 1
= -2 (x^2 + 6x + 9 ) + 19
Then, reduce it into the form of y=a(x-h)^2+k
The vertex is at (h,k)
OpenStudy (anonymous):
so the answer is -3,19
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