Question

Determine the solution set of (3x + 1)^2 - 100 = 0.

a) {3, -3}
b) {3, -11/3}
c) {-11/3, -3}

Answer 1

ok so this starts out just like the last problem we did, add over the 100, then take the square root of both sides, right? So you'll get two equations, because the square root of 100 can be either +10 or -10:\[3x+1=10\]and\[3x+1=-10\]then solve each of those for x. You good from there?

Answer 2

I got B

Answer 3

@caseyrt

Answer 4

got it!

Answer 5

thank you! @caseyrt