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the sum of a number and its reciprocal is 13. find the number?
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so its x+ 1/x= 13
but what do i do from there?
add and get \[\frac{x^2+1}{x}=13\]
then write \[x^2+1=13x\] so \[x^2-13x+1=0\] and solve for \(x\)
then use the quadratic formula you good from there?
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yeah, i used the quadratic formula and got 12.92, -.07 so i figured i was wrong somehow
i would go with \[\frac{13+\sqrt{165}}{2}\]
haha okay, thanks again!!!
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