Question

y + 3x = 0
y − 6 = −3x^2 how do i solve

Answer 1

you can write the first equation as \(y=-3x\) and then solve
\[-3x-6=-3x^2\]

Answer 2

add \(3x^2\) to ge t
\[3x^2-3x-6=0\] and then factor as
\[3(x^2-x-2)=0\]

Answer 3

that will help me get this ?

Answer 4

yes it will

Answer 5

solve
\[3(x-2)(x+1)=0\] and so there are two solution for \(x\) namely \(2\) or \(-1\)
now we have to find \(y\)

Answer 6

which is not hard, since we already know \(y=-3x\)

Answer 7

so if \(x=2\) then \(y=-3\times 2=-6\) and one solution is \((2,-6)\)

Answer 8

if \(x=-1\) then \(y=-3\times (-1)=3\) so another solution is \((-1,3)\)

Answer 9

so much work! thanks babe!