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Algebra 7 Online
OpenStudy (anonymous):

Find the number of real solutions for x^2-1=0

OpenStudy (nory):

First, factor. This is a difference of squares, so the factorization is (x+1)(x-1) = 0. Do you see what to do next?

OpenStudy (anonymous):

x^-1?

OpenStudy (nory):

Do you mean x^2 - 1?

OpenStudy (nory):

Oh.

OpenStudy (nory):

You mean x^-1, or 1/x.

OpenStudy (anonymous):

yea,

OpenStudy (anonymous):

x^2-1

OpenStudy (nory):

You want to factor that, right? So because it's a difference of squares, you factor it like (x+1)(x-1) = 0. Does that make sense?

OpenStudy (kenljw):

The square root of any number in +- , two roots and if your taking the square root of a positive real number the result will be a real number

OpenStudy (anonymous):

a real number or 2

OpenStudy (nory):

It will be 2 because the equation is quadratic and this equation happens to have 2 solutions.

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