A 15.0 cm long cylindrical glass tube, sealed at one end, is filled with ethanol. The mass of ethanol needed to fill the tube is found to be 11.86 g. The density of ethanol is 0.789 g/mL. Calculate the inner diameter of the tube in cm.

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anonymous · Answer

Please help me with my another problem

anonymous · Answer

attachment

anonymous · Answer

Thank you again

anonymous · Answer

I have lots of problem here qsx.
Can you help me? please

anonymous · Answer

when is all due?
i can help you with one more
i have pre-cal exam tomorrow

anonymous · Answer

The US quarter  has a mass of 5.67 g and his approximately 1.55mm thick. (A) how many quarters would have to be stacked to reach 575 ft. what is  the height of the washington monument? (B) how much would this weigh?(C) how much money would this stack contain(D) at the begging of 2007, the natl. depth was $8.7 trillion. How many stack like one describe would be necessary to pay off this debt?

anonymous · Answer

That's the problem qsx. That's the last one.

anonymous · Answer

lol piece of cake, wait 5 mins

anonymous · Answer

Ok, i can wait

anonymous · Answer

Hey, i need to go. I'm already late for my class, thank you for helping. ^_^ bye

anonymous · Answer

np prob, i am still solving

anonymous · Answer

@Festinger please help me with this problem

festinger · Answer

1 foot = 304.8mm

$$575feet * \frac{304.8}{1 foot}= 175260mm$$
this would be:
$$\frac{175260mm}{1.55mm/coin}= 113071 coins$$
and thus
$$113071*5.67=641112g=641kg$$

anonymous · Answer

The US quarter has a mass of 5.67 g and his approximately 1.55mm thick. (A) how many quarters would have to be stacked to reach 575 ft. what is the height of the washington monument? (B) how much would this weigh?(C) how much money would this stack contain(D) at the begging of 2007, the natl. depth was $8.7 trillion. How many stack like one describe would be necessary to pay off this debt?

@Festinger i mean with this problem. I'm so sorry :33

anonymous · Answer

I gave you the wrong one. I'm so sorry T_T

festinger · Answer

(c) it's worth whatever 113071 quarters is worth in dollars.
(d) take $8.7*10^12 divided by whatever one quarter is worth in $ and multiply by 1.55mm

anonymous · Answer

Ohh. Thank you so much ^_^

anonymous · Answer

By the way, how to solve the problem in letter B?

festinger · Answer

Take the number of coins times the weight of each coin. It's in one of my replies. I solved (a) and (b) in one reply, the (C) and (D) in the second.

anonymous · Answer

Okaay. :) thank you so much festinger. ^_^ you really helped me a lot.