Question

how do I solve the polynomial equation 6x^2-4x-9=x^2+3

Answer 1

\[6x^2-4x-9-x^2-3=0\]

Answer 2

\[5x^2-4x-12=0\]

Answer 3

\[x=(-b \pm \sqrt{b^2-4(a*c)})/2a\]

Answer 4

Thankyou, do I have to do that last step?

Answer 5

thats how you get x=what

Answer 6

5x^2-4x-12=0
two number that multiply to 5*(-12) but add to -4
those two numbers are -10 and 6
expand the middle term
5x^2-10x+6x-12=0
factor a 5x out of the first two terms and a 6 out of the last
5x(x-2)+6(x-2)=0
factor the (x-2) out of those two terms
(x-2)(5x+6)=0
so
x-2=0 and 5x+6=0
solve these
x = 2 and x = -6/5

Answer 7

c<0

Answer 8

@zzr0ck3r I didnt notice that..thank you

Answer 9

thanks @Krishnadas and @zzr0ck3r so much