how do i solve the polynomial equation x^2+9x+5=x-5

Question

anonymous · Answer

First you must set the equation equal to 0, so the x must be subtracted on each side:
x^2+9x+5=x-5 turns to x^2+8x+5=-5
Now to get rid of the pesky -5:
 x^2+8x+5=-5 turns to  x^2+8x+10=0
Remember when there's a negative you want to rid of, you add to both sides. When there's a positive you want to rid of, you subtract to both sides.
Now x^2+8x+10 cannot be factored out well because no numbers will add to +8 and multiply to +10 so you use the formula: [-b±√(b^2-4ac)]/2a
Now, using x^2+8x+10 as a form of y=ax^2+bx+c, you can determine:
1=a
8=b
10=c
Now plug in the numbers and solve for the equation.

anonymous · Answer

is the answer -8+- square root of 24/2?

anonymous · Answer

(-8±√24)/2

From my calculations, yes. I am not absolutely sure if this is the correct answer but I've worked it out thrice and came with the same answer.

anonymous · Answer

thankyou.