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Find the second derivative of the function f(v)=3v^2+4v-5/v
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do you know how to find the first derivative?
kind of not really
do i use the quotient rule?
f'(v)= 6v+4-5v^-2
then take the derivative of that
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f''(v)= 6-10v^-3
that's the final answer?
yup
My teacher gave us the answer an he put -10/v^2
to the third power, sorry!
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are you sure? because 3v^2 first derivative= 6v second derivative= 6 so it should be 6- that
I meant = -10/v^3
6-10/v^3 should be the answer
Alright thanks!
no problem!
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