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Use completing the square to solve the equation x^2 - 10x = -8. Which equation is used in the process? a) x2- 10x + 25 = 17 b) x2- 10x + 25 = -8 c) x2- 10x - 25 = -33
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x2- 10x + 25 = 17
howd you get that
I was going with the first one as well..
u had to add (b/2)^2 in this case (10/2)^2
Given that \[x^2 - 10x = -8. \rightarrow x^2 - 2 \times5 \times x = -8.\] comparing the middele term with 2ab we find a=x and b=5 since square of x is already given sq we need to add square of 5 on both sides so \[x^2 - 2 \times5 \times x + 5^2= 5^2-8.\] \[x^2 - 10x + 25= 25-8.\rightarrow x^2 - 10x + 25= 17\]
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a) x2- 10x + 25 = 17 ==> x2- 10x + 25- 17 ==> x2- 10x +8 ==> x2- 10x = -8
okay! thank you!
simplifying
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