Question

can anyone help me with the steps? Which do I distribute and which do I isolate?
-2(x-3)≥ 5 -(x+3)

Answer 1

distribute the -2 to x and -3

Answer 2

distribute the - or -1 to x and +3

Answer 3

You distribute both values and then solve.
-2(x-3)≥ 5 -(x+3)
This can become:
-2x+6 ≥ 5-x-3
Now we can add 2x to each side:
6 ≥ 5+x-3
Add 3 to 6:
9 ≥ 5+x
Now subtract 5:
4 ≥ x

Answer 4

then isolate the xs to one side and numbers to the other side

Answer 5

Wouldnt I combine like terms on the second line?

Answer 6

the 5 and -3?

Answer 7

@flixoe what happened to adding the 2x to both sides.... x+2x=3x?

Answer 8

You can simplify inequalities and equations in many different methods.
@mary.rojas I just keep them both negative then get rid of the larger negative to give the other side a positive x value.

Answer 9

seems like a short cut 4≥x is correct

Answer 10

oh ok :)

Answer 11

I feel like I missed a step

Answer 12

where?

Answer 13

I was adding 2x to both sides

Answer 14

That's what you are supposed to do. Were both your x values negative after distributing?

Answer 15

no positive ive done this 3 ways and got a diff answer everytime LOL

Answer 16

Thanks everyone