Question

Solve the equation sqr3 sinx = 1/2 sec x for 0 deg < x < 360 deg.

Answer 1

the magic of a calculator...lol

Answer 2

ok nvmd....idk
I have noooo idea what ur doing kid....

Answer 3

lol @leah

Answer 4

what kind of problem is it??

Answer 5

$$\bf \large {
\sqrt{3} sin(x) = \frac{1}{2}sec(x)\\
\sqrt{3} sin(x) = \frac{1}{2cos(x)}\\
sin(x)cos(x) = \frac{1}{2}\frac{1}{\sqrt{3}}
\implies \frac{a}{c}\frac{b}{c}\\
sin(x) = \frac{1}{2}\\
cos(x) = \frac{1}{\sqrt{3}}
}
$$

Answer 6

or the other way around

Answer 7

then just arcCosine and arcSine both sides to get the angles

Answer 8

\(\bf sin(x)cos(x) = \frac{1}{2}\frac{1}{\sqrt{3}}
\implies \frac{b}{c}\frac{a}{c}\)

had them backward :/

Answer 9

what kind of problem

Answer 10

Okay, so sin x = 1/sqr3 and cos x = 1/2?

Answer 11

or the other way around, either way will give 1/2 secx

Answer 12

if you recall your 45-45-90 rule and your 30-60-90 rule you'd know who those guys are :)

Answer 13

Okay, thanks.

Answer 14

yw