Question

Sorry I'm still having trouble on these problems

What is the value of b^2 - 4ac for the following equation?

2x^2 - 2x - 1 = 0

a) -4
b) 0
c) 12

I get that A= 2 B= -2 C= -1

Answer 1

it's [b ^{2}-4ac\] But I don't remember why or how.

To solve it it's easy, think of your equation in this way:
a is paired with x because x is earlier in the alphabet, so is a
b is paired with y because y is after x in the alphabet, as is b to a
and c is always your number on it's own.

Answer 2

by basic quadratic equation solving formula

For ax2 + bx + c = 0, the value of x is given by:


x1=(-b+(b^2-4ac))/2a X2=(-b-(b^2-4ac))/2a


x1=0.95
x2=0.786

Answer 3

So you need to find a,b, and c, and use the above formula
the a, b, and c come from
a x^2 + bx + c
so match your quadratic
2x^2 + 7x + 3 = 0

to find a,b, and c.

Answer 4

it is c

Answer 5

ty