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what expression defines the arithmetic series 4+8+12...
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an = dn + c Where d is the common difference between consecutive terms of the sequence, and c = a1 - d.
in sigma form
oh you want a summation
yes
does the series end at a number or does it go on infinitely?
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it ends at the fourth number but it doesnt give that number
so it would be 4,8,12,a4, correct?
yes
\[\sum_{n=1}^{4} 4n\]
just to make sure you understand, do you understand sigma notation?
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The n=1 means that the summation starts with the first term and ends with the term at the top (4), the equation used to represent the series would go to the right of that
thankyou :)
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