Solve the following quadratic equation using the quadratic formula and then choose the correct solution set. 6x^2 - 7x + 2 = 0 a) {-1/2,2/3} b) {1/2,2/3} c) {1/2,3/2}
quadratic formula is: \[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
In your problem, a = 6, b = -7, c = 2
I don't know why they ask to solve by quad formula when it is already factorable. That sort of defeats the purpose.
I keep getting weird answers
is it b?
Post your work and I will trouble shoot it.
Yes. It is b
Good job.
aright thanks. sry I didn't know how to type my work out
np
You can also factor it 6x^2 - 7x + 2 = 0 6x^2 - 4x - 3x + 2 = 0 2x(3x - 2) - 1(3x - 2) = 0 (3x - 2)(2x - 1) = 0 3x - 2 = 0 2x - 1 = 0 x = 2/3 x = 1/2 For your purposes, however, quad formula might be easier for you.
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