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Precalculus
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If the sine of an acute angle is 3/5 what is the cosine of that angle?
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what is it in fraction form?
\[(sinx)^2+(cosx)^2=1\]
so if sin of the angle is 3/5 then just put that into the identity and solve for (cosx)
it has to be either 4/5 2/5 root2/5 or 1/54
idk how
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ok I will show you :)
sinx=3/5
\[(\frac{ 3 }{ 5 })^2+(cosx)^2=1\]
\[\frac{ 9 }{ 25 }+(cosx)^2=1\]
\[(cosx)^2=1-(\frac{ 9 }{ 25 })\]
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\[(cosx)^2=\frac{ 16 }{ 25}\]
then take the square root of both sides!
(cosx)= ?
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