Question

Right Triangle Trigonometry Help Please

Answer 1

Well, starting off with the first problem, sin cos and tangent are all in reference to the angle you're using. You likely have heard of Soh Cah Toa as a mnemonic for remembering which trig function goes with which sides. Well, sin is opposite over hypotenuse. In reference to your angle A, the opposite is straight across and is little a, and the hypotenuse is always the longest side, which is little c. so the answer is a/c. Also know that you can solve that even without a picture. Little a and capital A, little b and capital B are ALWAYS straight across from one another. Little c is always the hypotenuse and big C is always the right angle.

Answer 2

For #2, you need to know that cotangent is the reciprocal of tangent. If tangent is opposite over adjacent, then cotangent is adjacent over opposite. Now in reference to angle B, adjacent would be 12, and opposite would be straight across at 5. So your answer is 12/5

Answer 3

#3. It again asks for sin, so we need opposite over hypotenuse. In reference to angle Z, the opposite is 8, and the hypotenuse is 10. So 8/10 is your fraction, which reduces to 4/5

Answer 4

#4. Tangent is opposite over adjacent. In reference to angle Y, straight across would be 6 and the adjacent would be 8, making the fraction 6/8, which reduces to 3/4.
Using sine = opp/hyp cosine = adj/hyp tan = opp/adj cot = adj/opp sec = hyp/adj, and csc = hyp/opp, you think you could figure out the last ones?

Answer 5

Im not sure, i've been struggling with this stuff. But thank you so much!

Answer 6

Well, I thought I would start you off. Not out to do ALL of the questions, but if you know which sides you need to use and that your sides are in reference to the angle you are using, there is not too much else that needs to be done. Once you realize what is what you'll catch on for sure :3