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jimthompson5910 (jim_thompson5910):
no don't distribute back
jimthompson5910 (jim_thompson5910):
factor further
OpenStudy (anonymous):
what would I factor?
jimthompson5910 (jim_thompson5910):
the two terms are 2x(x + 5) and 3(x + 5)
jimthompson5910 (jim_thompson5910):
what's common between them
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OpenStudy (anonymous):
the 5
OpenStudy (anonymous):
and x
jimthompson5910 (jim_thompson5910):
so the x+5
jimthompson5910 (jim_thompson5910):
you would factor that out to get
(2x+3)(x+5)
OpenStudy (anonymous):
thats the answer?
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jimthompson5910 (jim_thompson5910):
yes
2x^2 + 13x + 15
factors to
(2x+3)(x+5)
jimthompson5910 (jim_thompson5910):
expand out (2x+3)(x+5) for yourself and you'll see it simplifies to 2x^2 + 13x + 15
OpenStudy (anonymous):
Can you check an answer for me?
jimthompson5910 (jim_thompson5910):
sure
OpenStudy (anonymous):
5x2 − 2x − 7
First multiply 5 and -7.
5 * -7 = -35
Then get a factor of -35 where the sum will be -2.
-7 * 5 = -35 and -7 + 5 = 2
Then you will put -7x + 5x where -2x is.
5x^2 − -7x + 5x − 7
Then group the first two terms and you have to pull out x and group the last two terms and factor out 1.
5x2 − -7x + 5x − 7
x( 5x - 7) + 1( 5x - 7)
Then you will pull out 5x- 7 because that is the common factor and your answer is
(5x - 7) ( x + 1)
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jimthompson5910 (jim_thompson5910):
you have two minus signs next to each other in 5x^2 − -7x + 5x − 7
OpenStudy (anonymous):
oh okay thanks other than that?
jimthompson5910 (jim_thompson5910):
other than that, it looks great
jimthompson5910 (jim_thompson5910):
nice work
OpenStudy (anonymous):
thanks you so much!
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