The morgan silver dollar has a mass of 26.73 g. By law, it was required to contain 90% silver, with the remainder being copper (a) when the coin was minted in the late 1800s, silver was worth $1.18 per try ounce(31.1 g). At this price, what is the value of the silver in the silver dollar? (b) today, silver sell for about $13.25 per troy ounce. How many Morgan silver dollars are required to obtain $25.00 worth of pure silver?
What is a TRY ounce?? (just curious - i don't think its too important..)
okay i think i've got it - hang on still working on it
That's troy ounce. XD i'm sorry
Okay, i can always wait.
Have you got an answer so I can compare with you? If not - don't worry, I'll take you through my process:
Okay so we know that: TOTAL WEIGHT: 26.73g WEIGHT OF SILVER: (ONLY 90%) SO: O.9(26.730) = 24.057g right?
I didn't get the answer.
Does this make sense @louiseopura ?
Okay - never mind. So weight of silver in dollar = 24.057g Now we need to get this weight interms of the troy ounces..... to do this simply divide 24.057g by 31.1 = 0.7735.....grams Are you with me?
Now the question asks what is the price of the silver? So, simply multiply 0.7735.....grams by $1.18
For a) I got $0.91 (2 decimal places) which is about 90 cents
I'm sorry for the late reply @BarbaraKara our net is so slow.
I'm still with you
b) How many Morgan silver dollars are required to obtain $25.00 worth of pure silver? just divide 25.00 by 0.91277........ =27.389.... Therefore about 27.4 single dollars are needed to get 25 dollars worth of pure silver. Can you see how this works?
yeah. Uhmm, I'll be back later. Let's continue this later, can we? :) please? I need to eat
haha - okay - i might not be on though, just read back through, the answers are correct - im pretty sure ! :) have a nice dinner/lunch
I'm done eating @BarbaraKara let's continue. :)
Do you understand part a) ?
Yeah, i undertand. I'm calculating it.
Yay!
Haha. Thank you so much barbarakara ^_^ you really helped me alot.
You're welcome :)
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