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Find the probability for the experiment of tossing a six-sided die twice such that the sum is 5
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First. If you toss a die twice, how many possibilities are there?
For the pair of numbers
12
how many for the first die?
The first throw, you have six possibilities. The second, you also have six. But you have to multiply the two, because they are disjoint. (The outcome of one doesn't affect the outcome of the other.)
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fill in the table, there are \(6\times 6= 36\) possible outcomes count the ones where the sum is 5, then divide that number by 36
i got 1/9 @satellite73 is that right?
Yes. Good job
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