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OpenStudy (anonymous):
Solve the equation 1 over 3 x + 2 = 10 for x. 36 30 24 12
13 years ago
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OpenStudy (anonymous):
how do i do this?
13 years ago
OpenStudy (anonymous):
You should be able to move the 10 over and set the equation equal to 0.
Once you do that change 10 into a fraction.
You should end up with
(1/(3x+2)) - 10/1
Now make it so it has a common denominator by multiplying it by 3x+2.
Then solve.
13 years ago
OpenStudy (anonymous):
lol im confused now
13 years ago
OpenStudy (anonymous):
oh ok so then X would equal 28?
13 years ago
OpenStudy (anonymous):
\[\frac{ 1 }{ 3x+2 }= 10\]
\[\frac{ 1 }{3x+2 }-\frac{ 10 }{ 1 }=0\]
\[\frac{ 1 }{ 3x+2 }-(\frac{ 10 }{ 1 }\times \frac{ 3x+2 }{3x+2 })\]
13 years ago
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OpenStudy (anonymous):
so x= 28?
13 years ago
OpenStudy (anonymous):
Is that one of your answer options?
13 years ago
OpenStudy (anonymous):
oops nope
lol
13 years ago
OpenStudy (anonymous):
HAHAHAHA I suck at this
13 years ago
OpenStudy (anonymous):
Apparently I do too, I keep getting an improper fraction :(
Hold on, let me try it a different way
13 years ago
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OpenStudy (anonymous):
I multiplied by the resiprical then subtracted 2 on both sides
13 years ago
OpenStudy (anonymous):
Does only the 3x+2 = 10
or does the entire equation = 10?
13 years ago
OpenStudy (anonymous):
so it would go from this : 1 over 3 x + 2 = 10 for x.
to this: x+2=30
to this: x=28
but apparently its not right
13 years ago
OpenStudy (anonymous):
Well you dropped an x I think. It should be 30x
13 years ago
OpenStudy (anonymous):
no I left the x where it was but that may have been my mistake
13 years ago
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OpenStudy (anonymous):
no then it would be x= 0.0666666666666666666666
13 years ago
OpenStudy (anonymous):
|dw:1374851050959:dw|
13 years ago
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