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f(x) = 3x + 1; g(x) = 5x - 1 Find f/g. (f/g)(x) = ; domain {x|x ≠ - } (f/g)(x) = ; domain {x|x ≠ - } (f/g)(x) = ; domain {x|x ≠ } (f/g)(x) = ; domain {x|x ≠ }
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f/g =(3x+1)/(5x-1)
do you know what to do next?
no:(
We already have f/g, now we need to find the values that aren't in the domain. You can't divide by zero, right? So what happens if the denominator of\[\Large f/g =\frac{3x+1} {5x-1}\] equals zero? Then we're dividing by zero... so we can't have 5x-1=0.
ohh okay
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So can you now find the excluded x value? (the one that makes 5x-1=0)
yeah
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