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If a football is formed by rotating the sine curve y=sinx from zero to pi about the x axis, find the volume of the football
\[v = \int\limits_{0}^{\pi} y ^{2} dx\]
\[v = \int\limits_{0}^{\pi} \sin ^{2}x dx\]
Why is it those?
Use the disk method for around the x axis \[\Large V = \pi \int\limits_{a}^{b} R^2 dx\]where R is the radius, dx is the thickness of the disk, in this case your limits are 0 to pi, radius of the disk is sinx: \[\Large V = \pi \int\limits\limits_{0}^{\pi} (\sin x)^2 dx\] Easiest way to integrate sin^2 x is to use the trig identity \[\large \sin^2 x= \frac{ 1- \cos 2x }{ 2}\]
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Oh I see, thank you!
Final answer being 1/2(pi)^2 right?
Thanks @lncognlto and @agent0smith :)
1/2 x pi^2 is correct :)
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