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OpenStudy (anonymous):
!!!!!!!!!!!!!!!!FAN!!!!!!!!!!!!!!!!!!!MEDAL!!!!!!!!!!!!!!!!!! lol this looks so desperate anyways!
Factor completely: 2x3 + 10x2 + 4x + 20
2(x3 + 5x2 + 2x + 10)
2[(x + 5)(x2 + 2)]
(2x + 10)(x2 + 2)
(x + 5)(2x2 + 4)
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OpenStudy (jdoe0001):
let's first group them in 2 sets of 2 guys
\(\bf 2x^3 + 10x^2 + 4x + 20\\
(2x^3 + 10x^2) + (4x + 20)\)
can you get common factor for each pair there?
OpenStudy (anonymous):
yeah the x's
OpenStudy (anonymous):
am i right?
OpenStudy (jdoe0001):
just ahemm "x"s?
let's see how many common factors are there
\(\bf (2x^3 + 10x^2) + (4x + 20) \implies
(2xxx + (2)(5)xx) + (4x + (4)(5))\)
OpenStudy (jdoe0001):
so, can you get common factors for each pair?
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OpenStudy (anonymous):
lmaoo ahemm
OpenStudy (anonymous):
I'm going to be super honest. I am blind with variables and stuff like this
OpenStudy (jdoe0001):
ok, let's take one pair at a time
what's is common in these 2 terms => \(\bf 2xxx + (2)(5)xx \)
OpenStudy (anonymous):
x^3 andx^2
OpenStudy (anonymous):
2x^3 and 5x^2
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OpenStudy (anonymous):
I think the answer is D
OpenStudy (jdoe0001):
hmm well
2xxx, has x^3
10xx, only has 2 xx, so it doesn't have x^3 in common
OpenStudy (anonymous):
Lol leave me alone
OpenStudy (anonymous):
im jp
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