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How do you express sin 4theta in terms of theta
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You need two identities:\[\sin2x=2(\sin x)( \cos x)~~~and~~~\cos2x=\cos^2x-\sin^2x\]Once we have these, it's pretty direct.\[\sin 4x=2(\sin 2x)(\cos 2x)=4(sinx)(cosx)(\cos^2x-\sin^2x)\]
The identities come from formulas for sin of a sum and cos of a sum.
Do math every day.
Thanks, expressing in terms of theta confused me
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