Question

PLEASE HELP ME WITH THIS, GIVING AWARD
Graphing Exponential and Logarithmic Functions
Attachment below

Answer 1

So the first thing to notice is that the point (0,1) is still there. Because exponential graphs are always at (0,1) unless shifted left and right, you know there is no (x+_) or (x-_) as an exponent. You also know that y = 0 is an asymptote for an exponential graph. Butin your graph, that asymptote has been moved up 3. Also, the graph is reflected about the x-axis. This means that y is negative. So given those pieces of information, you should be able to piece something together for your graph. If not then can try and guide ya a little more :3

Answer 2

what is the equation that I plug these this? :o @Psymon

Answer 3

Well, you are really messing withyour original problem 2^x to get it to match the graph in blue. I was trying to give you hints on how to manipulate it :3 There is no left and right shift because the (0,1) point is still in tact. The asymptote hasbeen shifted up 3, and the y-value is negative.

Answer 4

@Hero