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Which point lies inside the circle with equation (x - 2)2 + (y + 3)2 = 4? a) (2, 0) b) (2, -4) c) (2, -5) d) (0, -3)
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i thought it was d
This is simple put the value in the equation. if result =0 it is on the circle result>0 outside the circle result <0 inside the circle You can complete it from here!
so i was right ?
option D gives you point on the circle! I think you have to find point inside the circle
so a? @ankit042
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f(x) = (x - 2)^2 + (y + 3)^2 - 4 try putting option A to this function
ok so its not a
NO when we put a we get f(x) >0
so b?
@ankit042
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@elizabethvilleda are you guessing the answers...or solving? :P Try to understand the concept
no im really trying
BTW option B is the correct answer!
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