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Mathematics 13 Online
OpenStudy (anonymous):

The red graph (1) is the graph of f(x) = 2x. Describe the transformation of the blue function (2) and write the equation of the graph.

OpenStudy (anonymous):

OpenStudy (dan815):

adfasdfasdfasdjkfklajsdlfaksf what a tiny cat

OpenStudy (dan815):

do u mena 2^x

OpenStudy (anonymous):

it has evidently been flipped around the x axis. as the vertical asymptote is in the other direction. and it is also now asymptoting at y=3 i.e it has been shifted up 3 so it has transformations of being flipped in the x axis and shifted up 3.

OpenStudy (dan815):

hmmm

OpenStudy (dan815):

there is also a shift in the x axis can u see it

OpenStudy (dan815):

its flipped moved up 3 and shifted 1 to the right so y=-2^(x+1) + 3

OpenStudy (dan815):

shifted 1 to the lefT*

OpenStudy (anonymous):

not a shift, a dilation factor

OpenStudy (dan815):

hmm

OpenStudy (anonymous):

or am i reading that wrong, hard to tell

OpenStudy (dan815):

ya i think u are wrong bro

OpenStudy (anonymous):

yep, almost certainly

OpenStudy (dan815):

happens :)

OpenStudy (dan815):

if u wanna do math get ready to make mistakes haha

OpenStudy (anonymous):

haha so so true. every day

OpenStudy (campbell_st):

actually the equation isn't y = -2^x + 3 the shift of + 3 is correct.. but the equation is actually y = -1*2^x + 3 if you think about -2^x x= 1 y = -2 x = 2 y = 4 so the function will alternate between negative and positive. By just multiplying the positive by a negative it well ensure that when approx x > 1.6 all values will be negative. hope this makes sense

OpenStudy (dan815):

dont forget that x shift too :)

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