Question

how do you do this (x^2x+7)(x-3)?

Answer 1

Multiply each term in the (x-3) times each term in the \((x^2+x+7)\). Assuming I have written the expressions correctly. Please verify that.

Answer 2

Use

FOIL

Answer 3

First
Outside
Inside
Last

Answer 4

sorry its supposed to look like this (x^2+2x+7)(x-3)

Answer 5

OK, The same instructions apply. First multiply the x by each term in the trinomial and then multiply the -3 by each term in the trinomial.

Answer 6

x^2-3x^2+2x+-6+2x+6x+7x-21?

Answer 7

\(x^2-3x^2+2x+-6+2x+6x+7x-21\)
`\(x^2-3x^2+2x+-6+2x+6x+7x-21\)`
Not quite right.
\(x \times x^2 = x^3\)

Answer 8

Recheck the rest of your multiplication, I think you may have added some instead?

Answer 9

x^3-3x^2+2x^2-6x+7x-21

Answer 10

Yes. Now, combine like terms.
\(x^3+2x^2+7x-3x^2-6x-21\)

Answer 11

x^3-x^2-x-21 @gypsy1274

Answer 12

When adding numbers with opposite signs, subtract the smaller from the larger and take the sign of the larger. \(-6+7=1\)
\(x^3-x^2+x-21\)

Answer 13

i see what i did is that the awnswer and is this the product?

Answer 14

Yes. That is the correct answer.

Answer 15

does it matter if the question was written like this: Find the product (x^2x+7)(x-3)

Answer 16

Order doesn't matter in multiplication or addition.

Answer 17

I want to recommend a book to you after you finish your test. It will help you to understand all this much better in preparation for your next class.
E-Z Alegbra published by Barron's. It is fun to read.

Answer 18

ok thank you

Answer 19

Your Welcome!

Answer 20

i just notice though on this page im on it saids this is the awnswer x^3-x^2+x-18
: http://www.jamestown.k12.nd.us/school/highschool/carpenter/ia64.pdf

Answer 21

I think that is a typo. I don't see how they got -18 when there is only one constant term from the multiplication and it is -21

Answer 22

ok good thank you