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Solve the system by the method of substitution. y = 2x + 3 y = 3x + 1
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is easy y=2x+3 === (3x + 1)=2x+3
just distribute
just subtract
no....solve for x by getting the x's on one side and everything else on the other side
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do not distribute
o kk
\[(2x+3)-(3x+1)=0\]
that will work as well
thx
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thats what we are here for :)
lol you guys are really nice
i got x=-2
how do i find y
3x + 1 = 2x + 3 3x - 2x = 3 - 1 x = 2 now sub 2 in for x in either of the original equations to find y
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o kk
sry
y=7
you got it...way to go :)
thx again
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no problem :)
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