please help me!!! let log(D^2/C^3*A) when logA=3 logB=2 logD=5

Question

campbell_st · Answer

well the law for division in logs

$$\log(\frac{a}{b}) = \log(a) - \log(b)$$

and the law for multiplication is 

$$\log(a \times b) = \log(a) + \log(b)$$

and lastly the law for powers

$$\log(a^b) = b \times \log(a)$$

just apply the laws to simplify the question then substitute the given values.

anonymous · Answer

still did not get an answer please help me through the steps

campbell_st · Answer

ok.. so its 

$$\log(D^2) - \log(C^3) + \log(A)$$

so just apply the power law... and then substitute your values.

anonymous · Answer

i got .97197 but the four answers they give you are 0.549, 4.44,1, and 19 which one would it be?

campbell_st · Answer

well its interesting how you got your answer as there is no information about logC

anonymous · Answer

i that is why i am confused