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OpenStudy (anonymous):
OpenStudy (anonymous):
Just remember, to be a valid distribution the probabilities must sum to one. that is,
\[\sum_{i=1}^{n}p \left( x _{i} \right)=1\]
OpenStudy (anonymous):
For which of these is that true?
OpenStudy (anonymous):
ok so wait whats p?
OpenStudy (anonymous):
Idk what to when the top of the summation has an N
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OpenStudy (anonymous):
Here's the difference... generally n is used for a sample and N is used for a population. In either case, it's just a number. You just have to sum over all possiblities.
OpenStudy (anonymous):
oh wait its just asking which probabilities add up to 1 right?
OpenStudy (anonymous):
Exactly!!!
OpenStudy (anonymous):
B, D, & E?
OpenStudy (anonymous):
I believe so
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OpenStudy (anonymous):
oh :p ok.
OpenStudy (anonymous):
ok so I just got a question asking for a variance of a table
OpenStudy (anonymous):
follow the exact steps u gave above right?
OpenStudy (anonymous):
not the excel ones. the steps u sent me when u thought I was talking about the FIRST question I posted.. the 2nd pic,, on the OTHER CHAT
OpenStudy (anonymous):
actually could u list the steps again in case to find variance
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OpenStudy (anonymous):
Yeah, send me the table and we can compare what we get.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
OpenStudy (anonymous):
so the 1st step is to find mean
OpenStudy (anonymous):
they give u mean which is 20.59
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OpenStudy (anonymous):
that's what I got
OpenStudy (anonymous):
well yea they give it 2 u. but how do use that t find variance again?
OpenStudy (anonymous):
sorry I really not to MOVE ON :(
OpenStudy (anonymous):
It's a process but you can get it!
OpenStudy (anonymous):
ok thank u! yay I did get 23.18 I think
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OpenStudy (anonymous):
one more!!!
OpenStudy (anonymous):
OpenStudy (anonymous):
true or false!
OpenStudy (anonymous):
nvm!
OpenStudy (anonymous):
OHHH FOR THE VALID PROBABILITY QUESTION I ASKED U ABOUT IMISSED IT!!!! CUZ IT SAID "WHICH IS NOT"!!! D:D:D:
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OpenStudy (anonymous):
This one is binomial. Ichiro either gets a hit or doesn't and the prob of a hit is 0.350 and he has 3 independent, identically distributed trials.
Therefore E(X) = Expected number of hits = n*p = 3* (0.350) = 1.05.
OpenStudy (anonymous):
Sorry about that, I missed it too!
OpenStudy (anonymous):
:(
OpenStudy (anonymous):
that and another question caused me to get a 72 on that assignment.
OpenStudy (anonymous):
but i can raise that if u can HELP ME W/ NORMAL CURVES :(
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OpenStudy (anonymous):
OpenStudy (anonymous):
Do you have a standard normal table?
OpenStudy (anonymous):
yes come to the new question I posted. its the same q. but on a new chat link. I tagged u