Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

pic is attached

OpenStudy (anonymous):

OpenStudy (anonymous):

Just remember, to be a valid distribution the probabilities must sum to one. that is, \[\sum_{i=1}^{n}p \left( x _{i} \right)=1\]

OpenStudy (anonymous):

For which of these is that true?

OpenStudy (anonymous):

ok so wait whats p?

OpenStudy (anonymous):

Idk what to when the top of the summation has an N

OpenStudy (anonymous):

Here's the difference... generally n is used for a sample and N is used for a population. In either case, it's just a number. You just have to sum over all possiblities.

OpenStudy (anonymous):

oh wait its just asking which probabilities add up to 1 right?

OpenStudy (anonymous):

Exactly!!!

OpenStudy (anonymous):

B, D, & E?

OpenStudy (anonymous):

I believe so

OpenStudy (anonymous):

oh :p ok.

OpenStudy (anonymous):

ok so I just got a question asking for a variance of a table

OpenStudy (anonymous):

follow the exact steps u gave above right?

OpenStudy (anonymous):

not the excel ones. the steps u sent me when u thought I was talking about the FIRST question I posted.. the 2nd pic,, on the OTHER CHAT

OpenStudy (anonymous):

actually could u list the steps again in case to find variance

OpenStudy (anonymous):

Yeah, send me the table and we can compare what we get.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

OpenStudy (anonymous):

so the 1st step is to find mean

OpenStudy (anonymous):

they give u mean which is 20.59

OpenStudy (anonymous):

that's what I got

OpenStudy (anonymous):

well yea they give it 2 u. but how do use that t find variance again?

OpenStudy (anonymous):

sorry I really not to MOVE ON :(

OpenStudy (anonymous):

It's a process but you can get it!

OpenStudy (anonymous):

ok thank u! yay I did get 23.18 I think

OpenStudy (anonymous):

one more!!!

OpenStudy (anonymous):

OpenStudy (anonymous):

true or false!

OpenStudy (anonymous):

nvm!

OpenStudy (anonymous):

OHHH FOR THE VALID PROBABILITY QUESTION I ASKED U ABOUT IMISSED IT!!!! CUZ IT SAID "WHICH IS NOT"!!! D:D:D:

OpenStudy (anonymous):

This one is binomial. Ichiro either gets a hit or doesn't and the prob of a hit is 0.350 and he has 3 independent, identically distributed trials. Therefore E(X) = Expected number of hits = n*p = 3* (0.350) = 1.05.

OpenStudy (anonymous):

Sorry about that, I missed it too!

OpenStudy (anonymous):

:(

OpenStudy (anonymous):

that and another question caused me to get a 72 on that assignment.

OpenStudy (anonymous):

but i can raise that if u can HELP ME W/ NORMAL CURVES :(

OpenStudy (anonymous):

OpenStudy (anonymous):

Do you have a standard normal table?

OpenStudy (anonymous):

yes come to the new question I posted. its the same q. but on a new chat link. I tagged u

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!