Question

solve. x^2-9x=-14

Answer 1

quadratic equation

Answer 2

use the formula

Answer 3

that is all

Answer 4

ok

Answer 5

you sure?

Answer 6

ill post what i get or when i get confused the formula is \[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] right

Answer 7

it's correct, good luck

Answer 8

ok im confused as to what to plug in a is the x^2 b is the -9 and c is -14. i dont know what to plug in for a

Answer 9

like how to write it

Answer 10

i see

Answer 11

1.x^2 = x^2

Answer 12

sooo....

Answer 13

a = 1

Answer 14

thats what i thought i should put but i wasnt sure

Answer 15

yea, that's everyones problem

Answer 16

i got \[\frac{ -9+\sqrt{137} }{ 2 }\]

Answer 17

do you have the answer to compare to?

Answer 18

like the choices?

Answer 19

i looked at the choices and now im confused

Answer 20

i mean, did your teacher give you the answer, so you can compare your answer to it

Answer 21

no this is summer school online so i dont have an instructer

Answer 22

alright..

Answer 23

do you think you have the right answer?

Answer 24

no thats none of the options i guess i have to solve for x

Answer 25

a. x=2 and -7
b. x=2 and 7
c. x=-2 and -7
d. x=-2 and 7

Answer 26

x^2-9x=-14 => x^2 - 9x +14 = 0

Answer 27

those are the choices

Answer 28

\[x=\frac{ -(-9) \pm \sqrt{-9^2-4(1)(14)} }{ 2(1) }\]

Answer 29

solve

Answer 30

thats what i did when i got the first answer

Answer 31

or what i thought was the answer

Answer 32

what is -(-9)?

Answer 33

9

Answer 34

try and solve it again

Answer 35

i got it x is 7 for one of them

Answer 36

alright

Answer 37

now how do i determine if its -2 or +2

Answer 38

should be 7 and 2

Answer 39

yeah but how do i find that

Answer 40

\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 41

see that +/- sign?

Answer 42

yeah

Answer 43

it means, you can choose to either add or subtract

Answer 44

to get 7, you added

Answer 45

oh do i subtract 5 from 9 instead of adding

Answer 46

exactly

Answer 47

ok got it thanks

Answer 48

np