Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

Solve the quadratic equation. 5x2 + 17x = –6

OpenStudy (anonymous):

set it equal to zero first

OpenStudy (anonymous):

5x^2 + 17x + 6 = 0?

OpenStudy (anonymous):

Now at this point, you would usually find two numbers that add to the x-coefficient and multiply to the constant, but the leading coefficient isn't 1, so you must multiply the leading coefficient with the constant.

OpenStudy (anonymous):

5x6 = 30 Now you can find two numbers that add to that x-coefficient (17) and multiply to 30.

OpenStudy (anonymous):

(5x+2)(x+3) help at all?

OpenStudy (anonymous):

Help to get to that answer?

OpenStudy (anonymous):

ax^2 + bx + c When A isn't 1, you must multiply A and C together, then find two numbers that multiply to the product of A and C and add to equal B. Does this make sense so far?

OpenStudy (anonymous):

no, i just factored it after I set it equal t zero. No idea why, just a desperate guess

OpenStudy (anonymous):

That is the correct answer, but you should understand how to reach it. Do you want to understand it or just go with the answer?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!