Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

Which of the following describes a set of data whose histogram approximates a normal curve? check all that apply A. The histogram of the data is exactly the same as the normal curve. B. The observations trail off at values far from the mean. C. All of the data values have to be positive. D. Most of the observations are near the mean of the data set. E. The sum of the data values must be 1.

OpenStudy (anonymous):

@pgpilot326

OpenStudy (anonymous):

I said B & E so far

OpenStudy (anonymous):

anything else? or is it right/ any changes?

OpenStudy (anonymous):

tricky question... B should be true and D should be true

OpenStudy (anonymous):

not E?

OpenStudy (anonymous):

no, the sum of the data values will be n times the mean.

OpenStudy (anonymous):

so it's ONLY B & D???

OpenStudy (anonymous):

yeah, that's my take.

OpenStudy (anonymous):

ok im gonna submit it :(

OpenStudy (anonymous):

go with your instincts

OpenStudy (anonymous):

I need one more opinion

OpenStudy (anonymous):

@primeralph

OpenStudy (anonymous):

@kropot72

OpenStudy (anonymous):

@hihihii

OpenStudy (anonymous):

@mebs

OpenStudy (anonymous):

is option E right?

OpenStudy (anonymous):

In a histogram the curve is not continuous... It must add up to 1 because that is the requirement of a normal curve...And of course all the values are positive because there are not negative decimals to add up to 1..

OpenStudy (anonymous):

what? yea, negative decimals CAN add up to one

OpenStudy (anonymous):

be careful... data values and probabilities are different things. data values can be negative, probabilities cannot.

OpenStudy (anonymous):

@mebs so what are ur choices??

OpenStudy (anonymous):

yea..

OpenStudy (anonymous):

I take on C & E.

OpenStudy (anonymous):

only c & e?

OpenStudy (anonymous):

...........

OpenStudy (anonymous):

It doesn't have to be far or close to the mean. I would say A could be a potential answer...|dw:1375069094071:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!